Answer
$\frac{1}{2}$
Work Step by Step
Set up the integration to find the area under the curve on the interval [1,2] (given by the shaded region)
$\int_1^2 (\frac{1}{x^2})dx$,
$[-x^{-1} ]_1^2$, Evaluate the definite integral
$(-\frac{1}{2})-(-1)$, Simplify
$\frac{1}{2}$
