#### Answer

The Mean Value Theorem does not apply to this function because this function is not continuous on the closed interval $[0, 6]$.

#### Work Step by Step

The Mean Value Theorem requires that this function must be continuous on the closed interval $[0, 6]$ and differentiable on the open interval $(0, 6)$. This function does not satisfy the first condition because this function has a nonremovable discontinuity (asymptote) at $x = 3$, which is in the closed interval $[0, 6]$. Therefore, the Mean Value Theorem does not apply to this function.