## Calculus 10th Edition

The Mean Value Theorem does not apply to this function because this function is not differentiable on the open interval $(0, 6)$.
The Mean Value Theorem requires that a function must be continuous on the closed interval $[0, 6]$and differentiable on the open interval $(0, 6)$. This function does not satisfy the second condition because the function has a cusp, which is not differentiable, at $x = 2$, which is in the open interval $(0, 6)$. Therefore, the Mean Value Theorem does not apply to this function.