Answer
True.
Work Step by Step
Since the derivative of a function with the highest term being $x^n$ has a highest term equal to $nx^{n-1}$, the derivative at max has $(n-1)$ roots and $(n-1)$ critical numbers.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.3 Exercises - Page 186: 94
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