Answer
See proof
Work Step by Step
If $f$ has a maximum at $x=c$, then for every $x$ in the interval $I$ we have
$f(c)\geq f(x)$
We multiply by $-1$:
$-f(c)\leq -f(x)$ for all $x\in I$.
Thus $-f$ attains a minimum at $x=c$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.1 Exercises - Page 169: 67
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