Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.1 Exercises - Page 168: 42

Answer

Absolute minimum at (0,1). No absolute maximum because 2 is undefined on the interval [0,2)

Work Step by Step

Graph the function on a graphing utility Evaluate the function at f(0), and f(2) $f(0)= 1$, $ f(2)=$undefined This means there is an absolute minimum at (0,1)
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