Answer
$f'(2)=-10.$
Work Step by Step
Using the Quotient Rule:
$f'(x)=\frac{(g'(x))(h(x))-(h'(x))(g(x))}{(h(x))^2}.$
$f'(2)=\frac{(-2)(-1)-(4)(3)}{(-1)^2}=-10.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 127: 105
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
