Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.2 Exercises - Page 116: 105

Answer

$\frac{dV}{ds} = 108$ $cm^{2}$

Work Step by Step

The exercise is simply asking for the rate of change in volume $V$ with respect to its sides $s$. Therefore, it's merely a matter of finding the first derivative of the function: $$V = s^{3}$$ $$(\frac{d}{ds})V = s^{3} (\frac{d}{ds})$$ $$\frac{dV}{ds} = 3s^{3 - 1} = 3s^{2}$$ For the value $s = 6cm$: $$\frac{dV}{ds} = 3(6)^{2} = 3(36) = 108 cm^{2}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.