Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 104: 54

Answer

$f(x)=x^2+4$

Work Step by Step

This quadratic function has a negative derivative when $x<0$ and a positive derivative when $x>0$. Also at $x=0$ the derivative is 0. To fulfill the requirement $f(0)=4$. We translated the graph up by 4 units. So the new graph is $f(x)=x^2+4$. This translation does not affect the derivative.
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