Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises: 32

Answer

$\\y=\frac{-3}{2}x+3$

Work Step by Step

$\\f(x)=\frac{6}{x+2}$ $\\f(x)=6(x+2)^{-1}$ $\\f'(x)=-6(x+2)^{-2}$ $\\f'(x)=\frac{-6}{(x+2)^{2}}$ $\\f'(0)=\frac{-6}{(0+2)^{2}}$ $\\f'(0)=\frac{-3}{2}$ Apply to straight line equation (y-y1)=m(x-x1) $\\y-3=\frac{-3}{2}x$ $\\y=\frac{-3}{2}x+3$
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