Answer
TRUE.
Work Step by Step
Since $x=t^2=t^2(cos^2t+sin^2t)=y^2+z^2$, we see that the statement is $ \fbox{true}$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 12 - Vector-Valued Functions - 12.1 Exercises - Page 823: 94
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