Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.7 Exercises - Page 809: 9

Answer

$$\left( {2\sqrt 2 , - \frac{\pi }{4}, - 4} \right)$$

Work Step by Step

$$\eqalign{ & \left( {2, - 2, - 4} \right) \cr & \left( {x,y,z} \right):{\text{ }}\left( {2, - 2, - 4} \right) \to x = 2,{\text{ }}y = - 2,{\text{ }}z = - 4 \cr & {\text{Rectangular to cylindrical}} \cr & {r^2} = {x^2} + {y^2} \to r = \sqrt {{{\left( 2 \right)}^2} + {{\left( { - 2} \right)}^2}} = 2\sqrt 2 \cr & \tan \theta = \frac{y}{x} \to \theta = {\tan ^{ - 1}}\left( {\frac{2}{{ - 2}}} \right) = - \frac{\pi }{4} \cr & z = z \to z = - 4 \cr & {\text{The cylindrical coordinates are:}} \cr & \left( {2\sqrt 2 , - \frac{\pi }{4}, - 4} \right) \cr} $$
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