Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.5 Exercises - Page 793: 109

Answer

TRUE.

Work Step by Step

Since the normal vector $\vec{v}$ is perpendicular to any vector lying in the plane, we know that the dot product is 0: $$ \vec{v} \cdot \vec{c} = 0$$ where c is an arbitrary vector which defines the plane.
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