Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.2 Exercises - Page 703: 5

Answer

$y=\frac{x^{\frac{2}{3}}}{2}$, Orientation is Up and Right as t increases in the positive direction.

Work Step by Step

Eliminate the parameter. Isolate for t. $x=t^3$ $t= \sqrt[x] 3$ Substitute for t. $y=\frac{t^2}{2}$ $y= \frac{x^{\frac{2}{3}}}{2}$
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