Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 40

Answer

$\lim\limits_{x\to6^-}\dfrac{x-6}{x^2-36}=\dfrac{1}{12}.$

Work Step by Step

$\lim\limits_{x\to6^-}\dfrac{x-6}{x^2-36}=\lim\limits_{x\to6^-}\dfrac{(x-6)}{(x-6)(x+6)}=\lim\limits_{x\to6^-}\dfrac{1}{x+6}$ $=\dfrac{1}{6^-+6}=\dfrac{1}{12}.$
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