Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 39

Answer

$\lim\limits_{x\to3^+}\dfrac{1}{x+3}=\dfrac{1}{6}.$

Work Step by Step

$\lim\limits_{x\to3^+}\dfrac{1}{x+3}=\dfrac{1}{3^++3}=\dfrac{1}{6}.$
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