Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 80: 61


The function is continuous when $a=7.$

Work Step by Step

$\lim\limits_{x\to1^-}f(x)=a(1^-)-4=a-4.$ $\lim\limits_{x\to1^+}f(x)=3(1^+)^2=3$ For the function to be continuous, $\lim\limits_{x\to1^+}f(x)=\lim\limits_{x\to1^-}f(x)\to$ $ a-4=3\to a=7.$
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