Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.2 Exercises - Page 58: 69

Answer

False since $$2 \neq 0$$

Work Step by Step

First off, it is best to let the following occur: f(x)=$$\left\{\begin{matrix} x-4 & if & x\neq 0\\ 0 & if & x=2 \end{matrix}\right.$$ Secondly, when it comes to $f(2)$, it already notes that $x=2$ when $f(x)=0$, which means the following: $$f(2)=0$$ Finally, when it comes to the limitations, it is based on when $x$ is actually approaching $2$, which means $x\rightarrow 2$, which can be simplified as the following: $$\begin{matrix} _{x\rightarrow 2}^{\lim}\textrm{f(x)}&x-4&\\ &=(2)-4&\\ &=2-4&\\ &=-2&\neq 0 \end{matrix}$$
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