#### Answer

A) Look at graph for solution
B) m1 = 1, m2 = 1.5, m3 = 2.5
C) 2, to improve result, get points closer to P.

#### Work Step by Step

A) $ y = 6(3)-(3)^{2} = 9$
$ y = 6(2.5)-(2.5)^{2} = 8.75$
$ y = 6(1.5)-(1.5)^{2} = 6.75$
B) $m1 = \frac{8-9}{2-3} = 1$
$m1 = \frac{8-8.75}{2-2.5} = 1.5$
$m1 = \frac{8-6.75}{2-1.5} = 2.5$
C) The slope of the tangent line at point P is approx. 2. To improve the approximation, look at the points closer to P.