## Calculus 10th Edition

Published by Brooks Cole

# Chapter 1 - Limits and Their Properties - 1.1 Exercises: 7

#### Answer

A) Look at graph for solution B) m1 = 1, m2 = 1.5, m3 = 2.5 C) 2, to improve result, get points closer to P.

#### Work Step by Step

A) $y = 6(3)-(3)^{2} = 9$ $y = 6(2.5)-(2.5)^{2} = 8.75$ $y = 6(1.5)-(1.5)^{2} = 6.75$ B) $m1 = \frac{8-9}{2-3} = 1$ $m1 = \frac{8-8.75}{2-2.5} = 1.5$ $m1 = \frac{8-6.75}{2-1.5} = 2.5$ C) The slope of the tangent line at point P is approx. 2. To improve the approximation, look at the points closer to P.

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