Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.4 Convergence Tests - Exercises Set 9.4 - Page 629: 22



Work Step by Step

Factoring out the constant $k^2 e^{-k^{k^3}}$ leaves $$\Sigma^m_{k=1} k^2 e^{-k^{k^3}}$$ This is a p-series with p<1. p is not greater than 1, so the series diverges.
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