Answer
$$y=x^2-2x $$
Work Step by Step
Given $$x \frac{dy}{dx} - y =x^2,\ \ \ \ \ y(1)=-1$$
Rewriting the equation
$$ \frac{dy}{dx} -\frac{1}{x} y=x$$
Since
\begin{align*}
\mu(x)&=e^{\int \frac{-1}{x} dx}\\
&=e^{-\ln x } \\
&=\frac{1}{x}
\end{align*}
Then
\begin{align*}
y\mu(x)&=\int \mu(x) q(x)dx\\
\frac{1}{x}y&=\int dx\\
&= x +c
\end{align*}
since $y(1)=-1,$ then $c=-2$
Hence $$y=x^2-2x $$