# Chapter 8 - Mathematical Modeling With Differential Equations - 8.1 Modeling With Differential Equations - Exercises Set 8.1 - Page 566: 6

True.

#### Work Step by Step

A solution to the differential equation is $y=-\frac{1}{2}$. $y'=0$, so $\frac{dy}{dx}=2y+1$ becomes $$0=2(-\frac{1}{2})+1=0$$ Therefore, there is a constant solution to the equation.

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