Answer
(b) $x=1$
$(a)(0,+\infty)$
Work Step by Step
(a)The integration evaluation gives $F (x)=\ lnx$, which is defined only for positive values, and therefore the function represents only an antiderivative on $(0,+\infty)$
(b)
The function crosses the $x$ axis if the function becomes zero. We know that $F (1)=0$.