Answer
\[
\int_{-3}^{3} 4 x(1-3 x) d x
\]
Work Step by Step
Replace the sum with an integer sign with the limits $a$ and $b, \Delta x_{k}$ with $d x$, and $x_{k}^{*}$ with $x$.
\[
\int_{-3}^{3} (-3 x+1) 4 x d x
\]
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