Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.2 The Indefinite Integral - Exercises Set 4.2 - Page 280: 69

Answer

tanx - x +C

Work Step by Step

We find: $\int$tan$^2$xdx =$\int($sec$^2$x-1)dx =$\int$sec$^2$xdx-$\int$1dx $\int$sec$^2$xdx=tanx+$C_{1}$ and $\int$1dx=x+$C_{2}$ So the expression is tanx - x +C
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