## Calculus, 10th Edition (Anton)

Published by Wiley

# Chapter 3 - The Derivative In Graphing And Applications - 3.3 Analysis Of Functions III: Rational Functions, Cusps, And Vertical Tangents - Exercises Set 3.3: 28

#### Answer

$\text{True}$

#### Work Step by Step

A function that has a vertical asymptote at $x=1$ cannot be defined at $x=1$. Therefore, the function is not continuous at $x=1$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.