Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 3 - The Derivative In Graphing And Applications - 3.1 Analysis Of Functions I: Increase, Decrease, and Concavity - Exercises Set 3.1 - Page 196: 44

Answer

See explanation.

Work Step by Step

Assuming $x_{1}0$ and $x_{2}>0,$ we then obtain $f\left(x_{2}\right)=\frac{1}{x_{1}}>\frac{1}{x_{2}}=$ $f\left(x_{1}\right)$ By definition $1.1.4,$ the function $f(x)=x^{2}$ is then decreasing for $x>0$
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