Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.8 Related Rates - Exercises Set 2.8 - Page 172: 1

Answer

a) $\frac{dy}{dt} = 6$ b) $\frac{dx}{dt} = -\frac{1}{3}$

Work Step by Step

a) By the chain rule, $\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}$. We solve for $\frac{dy}{dx}$ by differentiating the following equation by $\frac{d}{dx}$ $y=3x+5$ $\frac{dy}{dx} = 3$ Thus $\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt} = 3 \cdot 2 = 6$ b) We now differentiate both sides with respect to $t$: $y = 3x+5$ $\frac{dy}{dt} = 3\frac{dx}{dt}$ $\frac{dx}{dt} = \frac{dy}{dt}/3=-\frac{1}{3}$
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