Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6 - Page 160: 72

Answer

$ -sin(x)$

Work Step by Step

We are given that $cos(x) = sin(\frac{\pi}{2}-x)$. It is also true that $sin(x) = cos(\frac{\pi}{2}-x)$ as the sine of an angle is the cosine of the complementary angle and vice versa. We apply the chain rule: $\frac{d}{dx} cos(x) = \frac{d}{dx} sin(\frac{\pi}{2}-x) = cos(\frac{\pi}{2}-x)*(\frac{d}{dx} [\frac{\pi}{2} -x]) = -cos(\frac{\pi}{2}-x) = -sin(x)$
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