Answer
(a) $F'(3)=-7$
(b)$G'(3)=-8$
Work Step by Step
(a)$F(x)=f(g(x))$
$F'(x)=f'(g(x))\times{g'(x)}$
$F'(3)=f'(g(3))\times{g'(3)}$
$F'(3)=f'(5)\times{7}$
$F'(3)=-1\times{7}$
$F'(3)=-7$
(b)$G(x)=g(f(x))$
$G'(x)=g'(f(x))\times{f'(x)}$
$G'(3)=g'(f(3))\times{f'(3)}$
$G'(3)=g'(5)\times{-2}$
$G'(3)=4\times{-2}$
$G'(3)=-8$
