Answer
a. $f'(0.5) =1.54$
b. $f'(2.5) =-0.14$
Work Step by Step
We find:
a. $f'(0.5) = \frac{f(1)-f(0)}{1-0} = \frac{2.12-0.58}{1} = 1.54$
b. $f'(2.5) = \frac{f(3)-f(2)}{1-0} = \frac{2.2-2.34}{1} = -0.14$
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