Answer
a) $-4\cos7$
b) $ 2\cos7$
Work Step by Step
$f(x,y)=\sin (y^2-4x)$
a) $f_{x}=-4\cos(y^{2}-4x)$
$f_{x}(2,1)=-4\cos(1^{2}-4(2))=-4\cos7$
b) $f_{y}=2y\cos(y^{2}-4x)$
$f_{y}(2,1)=2(1)\cos(1^{2}-4(2))=2\cos7$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 13 - Partial Derivatives - 13.3 Partial Derivatives - Exercises Set 13.3 - Page 936: 13
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