Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 12 - Vector-Valued Functions - 12.1 Introduction To Vector-Valued Functions - Exercises Set 12.1 - Page 847: 43

Answer

Result $c = \frac{3}{2\pi}$,

Work Step by Step

For one complete turn of the helix, $\theta = 2\pi$: $\mathbf{r}(0) = a\cos 0 \mathbf{i} + a\sin 0 \mathbf{j} + 0 = a\mathbf{i}$ and $\mathbf{r}(2\pi) = a\cos 2\pi \mathbf{i} + a\sin 2\pi \mathbf{j} + c(2\pi)\mathbf{k} = a\mathbf{i} + c(2\pi) \mathbf{k}$ It is given that $2\pi c = 3 \implies c = \frac{3}{2\pi}$. Result: $c = \frac{3}{2\pi}$
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