Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 11 - Three-Dimensional Space; Vectors - 11.8 Cylindrical And Spherical Coordinates - Exercises Set 11.8 - Page 837: 44

Answer

The required equation in cylindrical form:-z=$\sqrt {r^2-1}$ The required equation in spherical form:-cos2$\phi$=-1/$\rho^2$

Work Step by Step

Given:-z=$\sqrt {x^2+y^2-1}$ For finding the equation in cylindrical form The co-ordinate of equation in cylindrical form x=rcosθ y=rsinθ z=$\sqrt {(rcosθ)^2+(rsinθ)^2-1}$ z=$\sqrt {r^2-1}$ For finding the equation in spherical form The co-ordinate of equation in spherical form z=$\rho$cos$\phi$ x=$\rho$cos$\theta$sin$\phi$ Y=$\rho$sin$\theta$sin$\phi$ z=$\sqrt {(ρcosθsinΦ)^2+(ρsinθsinΦ)^2-1}$ $\rho$cos$\phi$=$\sqrt {(ρcosθsinΦ)^2+(ρsinθsinΦ)^2-1}$ ($\rho$cos$\phi$)^2=(ρsinΦ)^2-1 After solving we get cos2$\phi$=-1/$\rho^2$
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