Answer
$$\eqalign{
& \left( {\bf{a}} \right) \cr
& {\text{foci : }}\left( { - \sqrt {21} ,0} \right){\text{ and }}\left( {\sqrt {21} ,0} \right) \cr
& {\text{Vertices: }}\left( { - 5,0} \right){\text{ and }}\left( {5,0} \right) \cr
& {\text{Ends of the minor axis: }}\left( {0, - 2} \right){\text{ and }}\left( {0,2} \right) \cr
& \left( {\bf{b}} \right) \cr
& {\text{foci : }}\left( {0, - 3\sqrt 3 } \right){\text{ and }}\left( {0,3\sqrt 3 } \right) \cr
& {\text{Vertices: }}\left( {0, - 6} \right){\text{ and }}\left( {0,6} \right) \cr
& {\text{Ends of the minor axis: }}\left( { - 3,0} \right){\text{ and }}\left( {3,0} \right) \cr} $$
Work Step by Step
$$\eqalign{
& \left( {\bf{a}} \right)\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{4} = 1 \cr
& {\text{The standard form of the ellipse is }}\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 \cr
& \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1:\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{4} = 1\,\,\,\,\,\,\,\, \to \,\,\,\,\,\,a = 5,\,\,\,\,b = 2 \cr
& {c^2} = {a^2} - {b^2} \cr
& {c^2} = 25 - 4 \cr
& {c^2} = 21 \cr
& c = \sqrt {21} \cr
& \cr
& {\text{With:}} \cr
& {\text{foci: }}\left( { - c,0} \right){\text{ and }}\left( {c,0} \right) \to {\text{foci : }}\left( { - \sqrt {21} ,0} \right){\text{ and }}\left( {\sqrt {21} ,0} \right) \cr
& {\text{Vertices: }}\left( { - a,0} \right){\text{ and }}\left( {a,0} \right) \to {\text{Vertices: }}\left( { - 5,0} \right){\text{ and }}\left( {5,0} \right) \cr
& {\text{Ends of the minor axis: }}\left( {0, - b} \right){\text{ and }}\left( {0,b} \right) \cr
& {\text{Ends of the minor axis: }}\left( {0, - 2} \right){\text{ and }}\left( {0,2} \right) \cr
& \cr
& \left( {\bf{b}} \right)4{x^2} + {y^2} = 36 \cr
& {\text{Divide both sides by 36}} \cr
& \frac{{4{x^2}}}{{{\text{36}}}} + \frac{{{y^2}}}{{{\text{36}}}} = \frac{{{\text{36}}}}{{{\text{36}}}} \cr
& \frac{{{x^2}}}{{\text{9}}} + \frac{{{y^2}}}{{{\text{36}}}} = {\text{1}} \cr
& {\text{The standard form of the ellipse is }}\frac{{{x^2}}}{{{b^2}}} + \frac{{{y^2}}}{{{a^2}}} = 1 \cr
& \frac{{{x^2}}}{{{b^2}}} + \frac{{{y^2}}}{{{a^2}}} = 1:\frac{{{x^2}}}{{\text{9}}} + \frac{{{y^2}}}{{{\text{36}}}} = {\text{1}}\,\,\,\,\,\,\, \to \,\,\,\,\,\,a = 6,\,\,\,\,b = 3 \cr
& {c^2} = {a^2} - {b^2} \cr
& {c^2} = 36 - 9 \cr
& {c^2} = 27 \cr
& c = 3\sqrt 3 \cr
& \cr
& {\text{With:}} \cr
& {\text{foci: }}\left( {0, - c} \right){\text{ and }}\left( {0,c} \right) \to {\text{foci : }}\left( {0, - 3\sqrt 3 } \right){\text{ and }}\left( {0,3\sqrt 3 } \right) \cr
& {\text{Vertices: }}\left( {0, - a} \right){\text{ and }}\left( {0,a} \right) \to {\text{Vertices: }}\left( {0, - 6} \right){\text{ and }}\left( {0,6} \right) \cr
& {\text{Ends of the minor axis: }}\left( { - b,0} \right){\text{ and }}\left( {b,0} \right) \cr
& {\text{Ends of the minor axis: }}\left( { - 3,0} \right){\text{ and }}\left( {3,0} \right) \cr} $$