## Calculus, 10th Edition (Anton)

$$f(x)=\frac{x+2}{x^{2}-4}$$ is continuous for all real numbers x except $x = 2$ , $x = -2.$
$$f(x)=\frac{x+2}{x^{2}-4}$$ The function being graphed is a rational function, and hence is continuous at every number where the denominator is nonzero. Solving the equation $$x^{2}-4=0$$ yields discontinuities at $x = 2$ and at $x = -2$ (Figure 1) $$f(x)=\frac{x+2}{x^{2}-4}$$ is continuous for all real numbers x except $x = 2$ , $x = -2$