Answer
(a) $(-0.05, 0.05)$
(b) $(-0.005, 0.005)$
(c) $(-0.0006, 0.00006)$
Work Step by Step
Step 1
We want x such that
$β£2π₯+3βπ(0)β£<πβΊβ£2π₯+3β3β£<π$
β
$βΊβ£2π₯β£<π$
$βΊ2β£π₯β£<π$
β
$βΊβ£π₯β£<π/2$
$β
βΊπ₯β(βπ/2,π/2)$
STEP 2:
Thus, the largest interval centered at $x = 0$ such that $|2x+3β Ζ (0)| <π$ for different π is
(a) $π= 0.1; (-0.05, 0.05)$
(b) $ π =0.01; (-0.005, 0.005)$
(c) $ π =0.0012; (-0.0006, 0.00006)$