Calculus, 10th Edition (Anton)

(a) $25$ degrees (b) $13$ degrees (c) $5$ degreees
(a) Since $v = 3$ mi/h, this falls under the condition that $0 \leq v \leq 3$. Therefore, WCT $= T = 25$. (b) Since $v=15$ mi/h, this falls under the condition that $3 < v$. Therefore, we can plug in $v=15$ and $T=25$ into the equation given: WCT $=35.74+0.6215(25)-35.75(15)^{0.16}+0.4275(15)^{0.16} = 12.623$ (rounded to three decimal places) Since the problem asks for the WCT to the nearest degree, the answer is $13$. (c) Since $v=46$ mi/h, this falls under the condition that $3 < v$. Therefore, we can plug in $v=46$ and $T=25$ into the equation given: WCT $=35.74+0.6215(25)-35.75(15)^{0.16}+0.4275(25)(46)^{0.16} = 5.032$ (rounded to three decimal places) Since the problem asks for the WCT to the nearest degree, the answer is $5$.