Answer
Based in the figure for problem 5 in part d:
$a= 24 sin(θ)$
$b = 24 cos(θ)$
Work Step by Step
Considering:
$cos(θ)= \frac{Adjacent leg}{Hypotenuse}$
$sin(θ)= \frac{Opposite leg}{Hypotenuse}$
then 24= hypotenuse
a= Opposite Leg
b= Adjacent Leg
