Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 397: 81

Answer

$f$ is not integrable on $[0,1]$

Work Step by Step

Let $x_i^*$ be a rational number in each subinterval of $[0,1]$ $\lim\limits_{n \to \infty}\sum_{i=1}^{n}f(x_i^*)\Delta x$ $= \lim\limits_{n \to \infty}\sum_{i=1}^{n}(0)\Delta x$ $= 0$ Let $x_i^*$ be an irrational number in each subinterval of $[0,1]$ $\lim\limits_{n \to \infty}\sum_{i=1}^{n}f(x_i^*)\Delta x$ $= \lim\limits_{n \to \infty}\frac{1}{n} \sum_{i=1}^{n}(1)$ $= \lim\limits_{n \to \infty}(\frac{1}{n})(n)$ $= \lim\limits_{n \to \infty}(1)$ $= 1$ Since the two limits are not equal, $f$ is not integrable on $[0,1]$
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