Answer
(a) $x^{2}$
(b) $\frac{1}{x}$
Work Step by Step
(a) $F(x)=x^{2}$ is an antiderivative of $f$ as $F'(x)=2x=f(x)$.
(b) $G(x)=\frac{1}{x}$ is an antiderivative of $g(x)$ as $G'(x)=-\frac{1}{x^{2}}=g(x)$.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises - Page 361: 2
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