Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 267: 46

Answer

$$f'(t)=\frac{2\cosh t}{(1-\sinh t)^2}$$

Work Step by Step

$f'(t)=\frac{d}{dt}\frac{1+\sinh t}{1-\sinh t}$ Using the quotient rule: $f'(t)=\frac{\cosh t(1-\sinh t)-(1+\sinh t)(-\cosh t)}{(1-\sinh t)^2}$ $=\frac{\cosh t-\cosh t\sinh t+\cosh t+\cosh t\sinh t}{(1-\sinh t)^2}$ $=\frac{2\cosh t}{(1-\sinh t)^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.