Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1130: 25

Answer

$\lt y^2cos(xy) ,sin(xy)+xycos(xy)\gt$

Work Step by Step

$f(x,y)=ysin(xy)$ $f_x(x,y)=y^2cos(xy)$ $f_y(x,y)=sin(xy)+xycos(xy)$ Gradient vector field of $f$ is: $\lt y^2cos(xy) ,sin(xy)+xycos(xy)\gt$
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