Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1130: 20

Answer

Graph $I$

Work Step by Step

Graph $I$ matches to $F(x,y,z)=i+2j+zk$ because all of the vectors in this field have constant $i$ and $j$ components, and the vectors above the xy-plane point upward, while the vectors below the plane point downward.
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