Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 16 - Review - Exercises - Page 1210: 7

Answer

$\frac{110}{3}$

Work Step by Step

$\int_Cxydx+y^2dy+yzdz=\int_0^1(2t+1)(4t)(2dt)+(4t)^2(4dt)+(4t)(3t-1)(3dt)$ $=[\frac{116t^3}{3}-2t^2]_0^1$ $=\frac{110}{3}$
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