Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 15 - Section 15.9 - Change of Variables in Multiple Integrals - 15.9 Exercise - Page 1116: 8

Answer

$x=\dfrac{u+2v}{5}$ and $y=\dfrac{3v-u}{10}$

Work Step by Step

We are given the parallelogram with vertices $(0,0), (4,3), (2,4), (-2,1)$. These vertices define the parallelogram in the form of the equations as follows: $-10 \lt 3x-4y \lt 0$; $0 \lt x+2y \lt 10$ Let us consider $u=3x-4y$ and $v=x+2y$ Thus, we have $-10 \lt u \lt 0$ and $0 \lt v \lt 10$ which shows a rectangle in the uv plane. Now multiply $v=x+2y$ with $2$ and add with $u=3x-4y$. This implies that $3x-4y+2x+4y=u+2v$ This gives: $x=\dfrac{u+2v}{5}$ Now multiply $v=x+2y$ with $-3$ and add with $u=3x-4y$. This implies that $3x-4y-3x-6y=u-3v$ This gives: $y=\dfrac{3v-u}{10}$ Hence, $x=\dfrac{u+2v}{5}$ and $y=\dfrac{3v-u}{10}$
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