Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 15 - Section 15.1 - Double Integrals over Rectangles - 15.1 Exercise - Page 1049: 9

Answer

$24\sqrt 2$

Work Step by Step

Plug in the limits for x and y into the integral: $\int\int\sqrt 2 dxdy$ With y limits from -1 to 5, and x limits from 2 to 6 Integrate the integral with respect to x first: $\int[\sqrt 2 x]dy$ with x limits from 2 to 6 $=\int4\sqrt 2 dy$ Integral with respect to y: $4\sqrt 2 y$ with limits -1 to 5 $=24\sqrt 2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.