Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.7 - Maximum and Minimum Values - 14.7 Exercise - Page 1018: 46

Answer

$(0,3,0), (0,-3,0)$

Work Step by Step

Formula to calculate the distance is: $D^2=x^2+y^2+z^2$ Also, $F=D^2=x^2+y^2+z^2$ This implies, $F_x=2x+z, F_z=x+2z$ After solving for $x$ and $z$, we get $x=0$ and $z=0$ Thus, $y^2=9+xz=9$ $implies y=\pm 3$ The required points are: $(0,3,0), (0,-3,0)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.