Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.6 - Directional Derivatives and the Gradient Vector - 14.6 Exercise - Page 1006: 20

Answer

$-2\sqrt2$

Work Step by Step

Formula to calculate the directional derivative: $D_uf=\nabla f(x,y) \cdot u$ or, from the Dot Product Theorem, $D_uf=║\nabla f(x,y)║║u║\cos θ$ where θ is the angle between ∇f(x,y) and the vector u. From the given figure, we have $\theta=180^\circ+45^\circ=225^\circ$ or $\dfrac{5\pi}{4}$. At $(2,2)$, $D_uf (2,2)=(4)(1) \cdot \cos\dfrac{5\pi}{4}$ Thus, $D_uf (2,2)=-2\sqrt2$
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