Answer
$4.65 Hz/s$ and $576.6$ Hz
Work Step by Step
Use the formula given in the problem.
Perceived frequency $=\dfrac{332+34}{332-40} \times 460=576.6$ Hz
Now, we have:
$\dfrac{d}{dt}[\dfrac{C+V_0}{C-f_s}f] =\dfrac{(C-f_s)(C+V_0)'-(C+V_0)(C-V_s)}{(C-f_s)^2}f$
Re-write as: $\dfrac{d}{dt}[\dfrac{C+V_0}{C-f_s}f] =\dfrac{(C-f_s)(V_0)'+(C+V_0)(V_s)}{(C-f_s)^2}f$
Plug in the given values:
$\dfrac{(332-40)(1.2)+(332+34)(1.4)}{(332-40)^2} \times 460=4.65 Hz/s$
Hence, $4.65 Hz/s$ and $576.6$ Hz
